Base | Representation |
---|---|
bin | 11001000110010111000111… |
… | …01110001101001101111001 |
3 | 21020102111202020022020112020 |
4 | 30203023203232031031321 |
5 | 24213300104433410033 |
6 | 313215502000305053 |
7 | 14424434332436055 |
oct | 1443134356151571 |
9 | 236374666266466 |
10 | 55194150294393 |
11 | 1664a786a29400 |
12 | 6234bb5312189 |
13 | 24a4a2ac10536 |
14 | d8b5a81c6c65 |
15 | 65aad6ea96b3 |
hex | 3232e3b8d379 |
55194150294393 has 12 divisors (see below), whose sum is σ = 80890600431984. Its totient is φ = 33451000178200.
The previous prime is 55194150294391. The next prime is 55194150294397. The reversal of 55194150294393 is 39349205149155.
It is not a de Polignac number, because 55194150294393 - 21 = 55194150294391 is a prime.
It is not an unprimeable number, because it can be changed into a prime (55194150294391) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 76025000043 + ... + 76025000768.
It is an arithmetic number, because the mean of its divisors is an integer number (6740883369332).
Almost surely, 255194150294393 is an apocalyptic number.
It is an amenable number.
55194150294393 is a deficient number, since it is larger than the sum of its proper divisors (25696450137591).
55194150294393 is a wasteful number, since it uses less digits than its factorization.
55194150294393 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 152050000836 (or 152050000825 counting only the distinct ones).
The product of its (nonzero) digits is 26244000, while the sum is 60.
The spelling of 55194150294393 in words is "fifty-five trillion, one hundred ninety-four billion, one hundred fifty million, two hundred ninety-four thousand, three hundred ninety-three".
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