Base | Representation |
---|---|
bin | 10000000100010000110… |
… | …01111110100100011001 |
3 | 1221202220220210100202111 |
4 | 20002020121332210121 |
5 | 33021041321401040 |
6 | 1101334453432321 |
7 | 54612113224615 |
oct | 10021031764431 |
9 | 1852826710674 |
10 | 552044325145 |
11 | 1a31366a2265 |
12 | 8aba663b6a1 |
13 | 400995b4241 |
14 | 1ca0d26a345 |
15 | e55ebe3dea |
hex | 808867e919 |
552044325145 has 4 divisors (see below), whose sum is σ = 662453190180. Its totient is φ = 441635460112.
The previous prime is 552044325137. The next prime is 552044325181. The reversal of 552044325145 is 541523440255.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 59897178121 + 492147147024 = 244739^2 + 701532^2 .
It is a cyclic number.
It is not a de Polignac number, because 552044325145 - 23 = 552044325137 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 552044325098 and 552044325107.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55204432510 + ... + 55204432519.
It is an arithmetic number, because the mean of its divisors is an integer number (165613297545).
Almost surely, 2552044325145 is an apocalyptic number.
It is an amenable number.
552044325145 is a deficient number, since it is larger than the sum of its proper divisors (110408865035).
552044325145 is a wasteful number, since it uses less digits than its factorization.
552044325145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 110408865034.
The product of its (nonzero) digits is 480000, while the sum is 40.
The spelling of 552044325145 in words is "five hundred fifty-two billion, forty-four million, three hundred twenty-five thousand, one hundred forty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •