Base | Representation |
---|---|
bin | 101000001010101010110… |
… | …1010010110011010111011 |
3 | 201112202022001111201120101 |
4 | 1100111111222112122323 |
5 | 1210421410323444403 |
6 | 15424022521540231 |
7 | 1106561252650645 |
oct | 120252552263273 |
9 | 21482261451511 |
10 | 5520470140603 |
11 | 1839244526630 |
12 | 751aa2344677 |
13 | 310769118a72 |
14 | 1512994b3895 |
15 | 989004db71d |
hex | 50555a966bb |
5520470140603 has 8 divisors (see below), whose sum is σ = 6094889269056. Its totient is φ = 4958144046600.
The previous prime is 5520470140597. The next prime is 5520470140607. The reversal of 5520470140603 is 3060410740255.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5520470140603 - 29 = 5520470140091 is a prime.
It is a super-3 number, since 3×55204701406033 (a number of 39 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (5520470140607) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3023257653 + ... + 3023259478.
It is an arithmetic number, because the mean of its divisors is an integer number (761861158632).
Almost surely, 25520470140603 is an apocalyptic number.
5520470140603 is a deficient number, since it is larger than the sum of its proper divisors (574419128453).
5520470140603 is a wasteful number, since it uses less digits than its factorization.
5520470140603 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6046517225.
The product of its (nonzero) digits is 100800, while the sum is 37.
Adding to 5520470140603 its reverse (3060410740255), we get a palindrome (8580880880858).
The spelling of 5520470140603 in words is "five trillion, five hundred twenty billion, four hundred seventy million, one hundred forty thousand, six hundred three".
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