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5520470140603 = 11836046517131
BaseRepresentation
bin101000001010101010110…
…1010010110011010111011
3201112202022001111201120101
41100111111222112122323
51210421410323444403
615424022521540231
71106561252650645
oct120252552263273
921482261451511
105520470140603
111839244526630
12751aa2344677
13310769118a72
141512994b3895
15989004db71d
hex50555a966bb

5520470140603 has 8 divisors (see below), whose sum is σ = 6094889269056. Its totient is φ = 4958144046600.

The previous prime is 5520470140597. The next prime is 5520470140607. The reversal of 5520470140603 is 3060410740255.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5520470140603 - 29 = 5520470140091 is a prime.

It is a super-3 number, since 3×55204701406033 (a number of 39 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (5520470140607) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3023257653 + ... + 3023259478.

It is an arithmetic number, because the mean of its divisors is an integer number (761861158632).

Almost surely, 25520470140603 is an apocalyptic number.

5520470140603 is a deficient number, since it is larger than the sum of its proper divisors (574419128453).

5520470140603 is a wasteful number, since it uses less digits than its factorization.

5520470140603 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6046517225.

The product of its (nonzero) digits is 100800, while the sum is 37.

Adding to 5520470140603 its reverse (3060410740255), we get a palindrome (8580880880858).

The spelling of 5520470140603 in words is "five trillion, five hundred twenty billion, four hundred seventy million, one hundred forty thousand, six hundred three".

Divisors: 1 11 83 913 6046517131 66511688441 501860921873 5520470140603