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552121402531 = 4312840032617
BaseRepresentation
bin10000000100011010000…
…00000000010010100011
31221210010021211022001111
420002031000000102203
533021221034340111
61101350245444151
754614040326206
oct10021500002243
91853107738044
10552121402531
111a3176157686
128b008410657
13400ac56026a
141ca195b193d
15e56686ba21
hex808d0004a3

552121402531 has 4 divisors (see below), whose sum is σ = 564961435192. Its totient is φ = 539281369872.

The previous prime is 552121402517. The next prime is 552121402541. The reversal of 552121402531 is 135204121255.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 552121402531 - 215 = 552121369763 is a prime.

It is a super-2 number, since 2×5521214025312 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 552121402493 and 552121402502.

It is not an unprimeable number, because it can be changed into a prime (552121402541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6420016266 + ... + 6420016351.

It is an arithmetic number, because the mean of its divisors is an integer number (141240358798).

Almost surely, 2552121402531 is an apocalyptic number.

552121402531 is a deficient number, since it is larger than the sum of its proper divisors (12840032661).

552121402531 is a wasteful number, since it uses less digits than its factorization.

552121402531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12840032660.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 552121402531 its reverse (135204121255), we get a palindrome (687325523786).

The spelling of 552121402531 in words is "five hundred fifty-two billion, one hundred twenty-one million, four hundred two thousand, five hundred thirty-one".

Divisors: 1 43 12840032617 552121402531