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552363140051 = 3591538615989
BaseRepresentation
bin10000000100110110110…
…10001010001111010011
31221210202010200211120222
420002123122022033103
533022214430440201
61101430243023255
754623034136262
oct10023332121723
91853663624528
10552363140051
111a328a657658
128b07536ab2b
134011a66bc08
141ca3d73a5d9
15e57cbbc91b
hex809b68a3d3

552363140051 has 4 divisors (see below), whose sum is σ = 553901756400. Its totient is φ = 550824523704.

The previous prime is 552363140011. The next prime is 552363140143. The reversal of 552363140051 is 150041363255.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 552363140051 - 218 = 552362877907 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 552363139993 and 552363140020.

It is not an unprimeable number, because it can be changed into a prime (552363140011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 769307636 + ... + 769308353.

It is an arithmetic number, because the mean of its divisors is an integer number (138475439100).

Almost surely, 2552363140051 is an apocalyptic number.

552363140051 is a deficient number, since it is larger than the sum of its proper divisors (1538616349).

552363140051 is a wasteful number, since it uses less digits than its factorization.

552363140051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1538616348.

The product of its (nonzero) digits is 54000, while the sum is 35.

The spelling of 552363140051 in words is "five hundred fifty-two billion, three hundred sixty-three million, one hundred forty thousand, fifty-one".

Divisors: 1 359 1538615989 552363140051