552444313340401 has 4 divisors (see below), whose sum is σ = 565291855511152. Its totient is φ = 539596771169652.

The previous prime is 552444313340371. The next prime is 552444313340411. The reversal of 552444313340401 is 104043313444255.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 552444313340401 - 2²¹ = 552444311243249 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (43), and also a Moran number because the ratio is a prime number: 12847542170707 = 552444313340401 / (5 + 5 + 2 + 4 + 4 + 4 + 3 + 1 + 3 + 3 + 4 + 0 + 4 + 0 + 1).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (552444313340411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6423771085311 + ... + 6423771085396.

It is an arithmetic number, because the mean of its divisors is an integer number (141322963877788).

Almost surely, 2^{552444313340401} is an apocalyptic number.

It is an amenable number.

552444313340401 is a deficient number, since it is larger than the sum of its proper divisors (12847542170751).

552444313340401 is a wasteful number, since it uses less digits than its factorization.

552444313340401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12847542170750.

The product of its (nonzero) digits is 1382400, while the sum is 43.

Adding to 552444313340401 its reverse (104043313444255), we get a palindrome (656487626784656).

The spelling of 552444313340401 in words is "five hundred fifty-two trillion, four hundred forty-four billion, three hundred thirteen million, three hundred forty thousand, four hundred one".