Base | Representation |
---|---|
bin | 101000001100110001111… |
… | …1110100111110011011011 |
3 | 201120012000010012211211011 |
4 | 1100121203332213303123 |
5 | 1211010202324144003 |
6 | 15430052530114351 |
7 | 1110111532130524 |
oct | 120314376476333 |
9 | 21505003184734 |
10 | 5525005303003 |
11 | 184016150322a |
12 | 75294911b9b7 |
13 | 31100c884204 |
14 | 1515a993384b |
15 | 98ab872346d |
hex | 50663fa7cdb |
5525005303003 has 4 divisors (see below), whose sum is σ = 5542657077448. Its totient is φ = 5507353528560.
The previous prime is 5525005303001. The next prime is 5525005303019. The reversal of 5525005303003 is 3003035005255.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5525005303003 - 21 = 5525005303001 is a prime.
It is a super-2 number, since 2×55250053030032 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5525005303001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8825886753 + ... + 8825887378.
It is an arithmetic number, because the mean of its divisors is an integer number (1385664269362).
Almost surely, 25525005303003 is an apocalyptic number.
5525005303003 is a deficient number, since it is larger than the sum of its proper divisors (17651774445).
5525005303003 is a wasteful number, since it uses less digits than its factorization.
5525005303003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17651774444.
The product of its (nonzero) digits is 33750, while the sum is 31.
The spelling of 5525005303003 in words is "five trillion, five hundred twenty-five billion, five million, three hundred three thousand, three".
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