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55253000001 = 318417666667
BaseRepresentation
bin110011011101010101…
…011101111101000001
312021121200021012221110
4303131111131331001
51401124232000001
641214411313533
73664135515363
oct633525357501
9167550235843
1055253000001
1121483972771
12a86014b8a9
135297151654
14296224cd33
151685b243d6
hexcdd55df41

55253000001 has 4 divisors (see below), whose sum is σ = 73670666672. Its totient is φ = 36835333332.

The previous prime is 55252999999. The next prime is 55253000017. The reversal of 55253000001 is 10000035255.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 55253000001 - 21 = 55252999999 is a prime.

It is a super-2 number, since 2×552530000012 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55253000021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9208833331 + ... + 9208833336.

It is an arithmetic number, because the mean of its divisors is an integer number (18417666668).

Almost surely, 255253000001 is an apocalyptic number.

It is an amenable number.

55253000001 is a deficient number, since it is larger than the sum of its proper divisors (18417666671).

55253000001 is a wasteful number, since it uses less digits than its factorization.

55253000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18417666670.

The product of its (nonzero) digits is 750, while the sum is 21.

Adding to 55253000001 its reverse (10000035255), we get a palindrome (65253035256).

The spelling of 55253000001 in words is "fifty-five billion, two hundred fifty-three million, one", and thus it is an aban number.

Divisors: 1 3 18417666667 55253000001