Base | Representation |
---|---|
bin | 110011011110010110… |
… | …010101001101001011 |
3 | 12021122212021002101211 |
4 | 303132112111031023 |
5 | 1401143110103111 |
6 | 41220215553551 |
7 | 3664433164351 |
oct | 633626251513 |
9 | 167585232354 |
10 | 55270003531 |
11 | 21492526776 |
12 | a86598b8b7 |
13 | 529a825c02 |
14 | 29645d77d1 |
15 | 1687382521 |
hex | cde59534b |
55270003531 has 4 divisors (see below), whose sum is σ = 55935907272. Its totient is φ = 54604099792.
The previous prime is 55270003519. The next prime is 55270003549. The reversal of 55270003531 is 13530007255.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 55270003531 - 25 = 55270003499 is a prime.
It is a super-2 number, since 2×552700035312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 55270003493 and 55270003502.
It is not an unprimeable number, because it can be changed into a prime (55270003031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 332951746 + ... + 332951911.
It is an arithmetic number, because the mean of its divisors is an integer number (13983976818).
Almost surely, 255270003531 is an apocalyptic number.
55270003531 is a deficient number, since it is larger than the sum of its proper divisors (665903741).
55270003531 is an equidigital number, since it uses as much as digits as its factorization.
55270003531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 665903740.
The product of its (nonzero) digits is 15750, while the sum is 31.
The spelling of 55270003531 in words is "fifty-five billion, two hundred seventy million, three thousand, five hundred thirty-one".
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