Base | Representation |
---|---|
bin | 11001001001011100010001… |
… | …10111110000110000011011 |
3 | 21020210121222002200101002201 |
4 | 30210232020313300300123 |
5 | 24222013400031130003 |
6 | 313340245220311031 |
7 | 14435202362320240 |
oct | 1444561067606033 |
9 | 236717862611081 |
10 | 55300000255003 |
11 | 16690664526499 |
12 | 6251616242477 |
13 | 24b19c96a4c1a |
14 | d9276a15b5c7 |
15 | 65d72ea90b1d |
hex | 324b88df0c1b |
55300000255003 has 4 divisors (see below), whose sum is σ = 63200000291440. Its totient is φ = 47400000218568.
The previous prime is 55300000255001. The next prime is 55300000255057. The reversal of 55300000255003 is 30055200000355.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 55300000255003 - 21 = 55300000255001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55300000255001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3950000018208 + ... + 3950000018221.
It is an arithmetic number, because the mean of its divisors is an integer number (15800000072860).
Almost surely, 255300000255003 is an apocalyptic number.
55300000255003 is a deficient number, since it is larger than the sum of its proper divisors (7900000036437).
55300000255003 is an equidigital number, since it uses as much as digits as its factorization.
55300000255003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7900000036436.
The product of its (nonzero) digits is 11250, while the sum is 28.
Adding to 55300000255003 its reverse (30055200000355), we get a palindrome (85355200255358).
The spelling of 55300000255003 in words is "fifty-five trillion, three hundred billion, two hundred fifty-five thousand, three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •