Base | Representation |
---|---|
bin | 110011100000010100… |
… | …001100111111110001 |
3 | 12021202011100111010002 |
4 | 303200110030333301 |
5 | 1401230032000144 |
6 | 41223355115345 |
7 | 3665313513203 |
oct | 634024147761 |
9 | 167664314102 |
10 | 55303000049 |
11 | 214aa113520 |
12 | a874a42b55 |
13 | 52a4609a8b |
14 | 2968b46773 |
15 | 168a1ee14e |
hex | ce050cff1 |
55303000049 has 16 divisors (see below), whose sum is σ = 64655072640. Its totient is φ = 46789839360.
The previous prime is 55302999991. The next prime is 55303000061. The reversal of 55303000049 is 94000030355.
55303000049 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 55303000049 - 216 = 55302934513 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 55302999985 and 55303000030.
It is not an unprimeable number, because it can be changed into a prime (55303000069) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2944544 + ... + 2963265.
It is an arithmetic number, because the mean of its divisors is an integer number (4040942040).
Almost surely, 255303000049 is an apocalyptic number.
It is an amenable number.
55303000049 is a deficient number, since it is larger than the sum of its proper divisors (9352072591).
55303000049 is a wasteful number, since it uses less digits than its factorization.
55303000049 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5907880.
The product of its (nonzero) digits is 8100, while the sum is 29.
The spelling of 55303000049 in words is "fifty-five billion, three hundred three million, forty-nine", and thus it is an aban number.
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