Base | Representation |
---|---|
bin | 10000000110010000000… |
… | …01000000001111101001 |
3 | 1221212200021220111012111 |
4 | 20003020001000033221 |
5 | 33030233022121413 |
6 | 1102032415242321 |
7 | 54650422230556 |
oct | 10031001001751 |
9 | 1855607814174 |
10 | 553111520233 |
11 | 1a3634040778 |
12 | 8b243b193a1 |
13 | 4020971a31c |
14 | 1cab0ca9a2d |
15 | e5c3749d3d |
hex | 80c80403e9 |
553111520233 has 4 divisors (see below), whose sum is σ = 553113547408. Its totient is φ = 553109493060.
The previous prime is 553111520197. The next prime is 553111520249. The reversal of 553111520233 is 332025111355.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-553111520233 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 553111520195 and 553111520204.
It is not an unprimeable number, because it can be changed into a prime (553111500233) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 526191 + ... + 1176052.
It is an arithmetic number, because the mean of its divisors is an integer number (138278386852).
Almost surely, 2553111520233 is an apocalyptic number.
It is an amenable number.
553111520233 is a deficient number, since it is larger than the sum of its proper divisors (2027175).
553111520233 is a wasteful number, since it uses less digits than its factorization.
553111520233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2027174.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 553111520233 its reverse (332025111355), we get a palindrome (885136631588).
The spelling of 553111520233 in words is "five hundred fifty-three billion, one hundred eleven million, five hundred twenty thousand, two hundred thirty-three".
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