Base | Representation |
---|---|
bin | 11001001010000111101100… |
… | …11010111100011111010011 |
3 | 21020212212010210210002212022 |
4 | 30211003312122330133103 |
5 | 24222404121113443443 |
6 | 313355102410122055 |
7 | 14436656161540454 |
oct | 1445036632743723 |
9 | 236785123702768 |
10 | 55323313031123 |
11 | 1669a537a26215 |
12 | 625604172032b |
13 | 24b3c734b61c7 |
14 | d9393c3c712b |
15 | 65e146584e68 |
hex | 3250f66bc7d3 |
55323313031123 has 4 divisors (see below), whose sum is σ = 55323378655968. Its totient is φ = 55323247406280.
The previous prime is 55323313031111. The next prime is 55323313031143. The reversal of 55323313031123 is 32113031332355.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 55323313031123 - 212 = 55323313027027 is a prime.
It is a super-2 number, since 2×553233130311232 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55323313031143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31531211 + ... + 33239492.
It is an arithmetic number, because the mean of its divisors is an integer number (13830844663992).
Almost surely, 255323313031123 is an apocalyptic number.
55323313031123 is a deficient number, since it is larger than the sum of its proper divisors (65624845).
55323313031123 is an equidigital number, since it uses as much as digits as its factorization.
55323313031123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65624844.
The product of its (nonzero) digits is 72900, while the sum is 35.
Adding to 55323313031123 its reverse (32113031332355), we get a palindrome (87436344363478).
The spelling of 55323313031123 in words is "fifty-five trillion, three hundred twenty-three billion, three hundred thirteen million, thirty-one thousand, one hundred twenty-three".
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