Base | Representation |
---|---|
bin | 11001001010010110110001… |
… | …01001000001101001111011 |
3 | 21020220122000122010101211001 |
4 | 30211023120221001221323 |
5 | 24223022203223343121 |
6 | 313402521253345431 |
7 | 14440363520202142 |
oct | 1445133051015173 |
9 | 236818018111731 |
10 | 55331403340411 |
11 | 166a2a09776340 |
12 | 625771b038277 |
13 | 24b4962658c73 |
14 | d940a8a7c759 |
15 | 65e46b96d991 |
hex | 3252d8a41a7b |
55331403340411 has 8 divisors (see below), whose sum is σ = 60430045718448. Its totient is φ = 50244180096000.
The previous prime is 55331403340403. The next prime is 55331403340487. The reversal of 55331403340411 is 11404330413355.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 55331403340411 - 23 = 55331403340403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55331403340511) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2854773270 + ... + 2854792651.
It is an arithmetic number, because the mean of its divisors is an integer number (7553755714806).
Almost surely, 255331403340411 is an apocalyptic number.
55331403340411 is a deficient number, since it is larger than the sum of its proper divisors (5098642378037).
55331403340411 is a wasteful number, since it uses less digits than its factorization.
55331403340411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5709566813.
The product of its (nonzero) digits is 129600, while the sum is 37.
Adding to 55331403340411 its reverse (11404330413355), we get a palindrome (66735733753766).
The spelling of 55331403340411 in words is "fifty-five trillion, three hundred thirty-one billion, four hundred three million, three hundred forty thousand, four hundred eleven".
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