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55334023036153 = 59489993014147
BaseRepresentation
bin11001001010011011101001…
…10010010111110011111001
321020220212210012112201210021
430211031310302113303321
524223043034344124103
6313404033234450441
714440515450224101
oct1445156462276371
9236825705481707
1055334023036153
11166a40334a3544
126258130433a21
1324b4c8c3069a4
14d9427696a201
1565e57193ebbd
hex325374c97cf9

55334023036153 has 4 divisors (see below), whose sum is σ = 55334116645200. Its totient is φ = 55333929427108.

The previous prime is 55334023036151. The next prime is 55334023036183. The reversal of 55334023036153 is 35163032043355.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 55334023036153 - 21 = 55334023036151 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55334023036151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45912175 + ... + 47101972.

It is an arithmetic number, because the mean of its divisors is an integer number (13833529161300).

Almost surely, 255334023036153 is an apocalyptic number.

It is an amenable number.

55334023036153 is a deficient number, since it is larger than the sum of its proper divisors (93609047).

55334023036153 is an equidigital number, since it uses as much as digits as its factorization.

55334023036153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 93609046.

The product of its (nonzero) digits is 1458000, while the sum is 43.

The spelling of 55334023036153 in words is "fifty-five trillion, three hundred thirty-four billion, twenty-three million, thirty-six thousand, one hundred fifty-three".

Divisors: 1 594899 93014147 55334023036153