Base | Representation |
---|---|
bin | 101000010000101101101… |
… | …0101100000000000110011 |
3 | 201120222210122212002121101 |
4 | 1100201123111200000303 |
5 | 1211130001230140201 |
6 | 15434010522305231 |
7 | 1110531024662326 |
oct | 120413325400063 |
9 | 21528718762541 |
10 | 5533450240051 |
11 | 18437a5449448 |
12 | 754505358217 |
13 | 311a57340696 |
14 | 151b6b33c7bd |
15 | 98e0ed0bd01 |
hex | 5085b560033 |
5533450240051 has 4 divisors (see below), whose sum is σ = 5616039049672. Its totient is φ = 5450861430432.
The previous prime is 5533450240049. The next prime is 5533450240061. The reversal of 5533450240051 is 1500420543355.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5533450240051 - 21 = 5533450240049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5533450240001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41294404710 + ... + 41294404843.
It is an arithmetic number, because the mean of its divisors is an integer number (1404009762418).
Almost surely, 25533450240051 is an apocalyptic number.
5533450240051 is a deficient number, since it is larger than the sum of its proper divisors (82588809621).
5533450240051 is an equidigital number, since it uses as much as digits as its factorization.
5533450240051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82588809620.
The product of its (nonzero) digits is 180000, while the sum is 37.
The spelling of 5533450240051 in words is "five trillion, five hundred thirty-three billion, four hundred fifty million, two hundred forty thousand, fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •