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55340497 = 297326141
BaseRepresentation
bin1101001100011…
…0110111010001
310212010120220001
43103012313101
5103131343442
65254050001
71241246362
oct323066721
9125116801
1055340497
1129269153
1216649901
13b608174
1474c7b69
154cd22b7
hex34c6dd1

55340497 has 8 divisors (see below), whose sum is σ = 58035240. Its totient is φ = 52698240.

The previous prime is 55340489. The next prime is 55340501. The reversal of 55340497 is 79404355.

It can be written as a sum of positive squares in 4 ways, for example, as 14776336 + 40564161 = 3844^2 + 6369^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 55340497 - 23 = 55340489 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55340437) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10954 + ... + 15187.

It is an arithmetic number, because the mean of its divisors is an integer number (7254405).

Almost surely, 255340497 is an apocalyptic number.

It is an amenable number.

55340497 is a deficient number, since it is larger than the sum of its proper divisors (2694743).

55340497 is a wasteful number, since it uses less digits than its factorization.

55340497 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26243.

The product of its (nonzero) digits is 75600, while the sum is 37.

The square root of 55340497 is about 7439.1193699254. The cubic root of 55340497 is about 381.0784163126.

Subtracting from 55340497 its sum of digits (37), we obtain a triangular number (55340460 = T10520).

The spelling of 55340497 in words is "fifty-five million, three hundred forty thousand, four hundred ninety-seven".

Divisors: 1 29 73 2117 26141 758089 1908293 55340497