Base | Representation |
---|---|
bin | 11001001010101110111001… |
… | …11100001000101100111011 |
3 | 21020221212110122001020021201 |
4 | 30211113130330020230323 |
5 | 24223230222223021023 |
6 | 313412503111315031 |
7 | 14441332562101525 |
oct | 1445273474105473 |
9 | 236855418036251 |
10 | 55344360360763 |
11 | 166a8458665521 |
12 | 625a13637ba77 |
13 | 24b5c48b5cb06 |
14 | d9497781aa15 |
15 | 65e979230bad |
hex | 3255dcf08b3b |
55344360360763 has 4 divisors (see below), whose sum is σ = 55346137724520. Its totient is φ = 55342582997008.
The previous prime is 55344360360703. The next prime is 55344360360791. The reversal of 55344360360763 is 36706306344355.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 55344360360763 - 213 = 55344360352571 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55344360360703) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 888635170 + ... + 888697447.
It is an arithmetic number, because the mean of its divisors is an integer number (13836534431130).
Almost surely, 255344360360763 is an apocalyptic number.
55344360360763 is a deficient number, since it is larger than the sum of its proper divisors (1777363757).
55344360360763 is a wasteful number, since it uses less digits than its factorization.
55344360360763 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1777363756.
The product of its (nonzero) digits is 48988800, while the sum is 55.
The spelling of 55344360360763 in words is "fifty-five trillion, three hundred forty-four billion, three hundred sixty million, three hundred sixty thousand, seven hundred sixty-three".
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