Base | Representation |
---|---|
bin | 11001001010101111100110… |
… | …10000001011011011010011 |
3 | 21020221220102201110022202221 |
4 | 30211113303100023123103 |
5 | 24223232004041313210 |
6 | 313413004203121511 |
7 | 14441345056044220 |
oct | 1445276320133323 |
9 | 236856381408687 |
10 | 55344734713555 |
11 | 166a862aa032a1 |
12 | 625a21b813297 |
13 | 24b5ca8591741 |
14 | d949b1426947 |
15 | 65e99c02a1da |
hex | 3255f340b6d3 |
55344734713555 has 16 divisors (see below), whose sum is σ = 76040109815040. Its totient is φ = 37881295556832.
The previous prime is 55344734713483. The next prime is 55344734713591. The reversal of 55344734713555 is 55531743744355.
It is not a de Polignac number, because 55344734713555 - 221 = 55344732616403 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 55344734713493 and 55344734713502.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1445390485 + ... + 1445428774.
It is an arithmetic number, because the mean of its divisors is an integer number (4752506863440).
Almost surely, 255344734713555 is an apocalyptic number.
55344734713555 is a deficient number, since it is larger than the sum of its proper divisors (20695375101485).
55344734713555 is a wasteful number, since it uses less digits than its factorization.
55344734713555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2890819818.
The product of its digits is 264600000, while the sum is 61.
The spelling of 55344734713555 in words is "fifty-five trillion, three hundred forty-four billion, seven hundred thirty-four million, seven hundred thirteen thousand, five hundred fifty-five".
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