Base | Representation |
---|---|
bin | 10000000111000001111… |
… | …01100010111110010011 |
3 | 1221220202110102201022010 |
4 | 20003200331202332103 |
5 | 33032112142404212 |
6 | 1102142125514003 |
7 | 54663663513432 |
oct | 10034075427623 |
9 | 1856673381263 |
10 | 553530044307 |
11 | 1a3829309039 |
12 | 8b340112903 |
13 | 402753462c6 |
14 | 1cb106d3119 |
15 | e5ea36c03c |
hex | 80e0f62f93 |
553530044307 has 4 divisors (see below), whose sum is σ = 738040059080. Its totient is φ = 369020029536.
The previous prime is 553530044273. The next prime is 553530044317. The reversal of 553530044307 is 703440035355.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 553530044307 - 28 = 553530044051 is a prime.
It is a super-2 number, since 2×5535300443072 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (553530044317) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92255007382 + ... + 92255007387.
It is an arithmetic number, because the mean of its divisors is an integer number (184510014770).
Almost surely, 2553530044307 is an apocalyptic number.
553530044307 is a deficient number, since it is larger than the sum of its proper divisors (184510014773).
553530044307 is a wasteful number, since it uses less digits than its factorization.
553530044307 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 184510014772.
The product of its (nonzero) digits is 378000, while the sum is 39.
The spelling of 553530044307 in words is "five hundred fifty-three billion, five hundred thirty million, forty-four thousand, three hundred seven".
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