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553530044307 = 3184510014769
BaseRepresentation
bin10000000111000001111…
…01100010111110010011
31221220202110102201022010
420003200331202332103
533032112142404212
61102142125514003
754663663513432
oct10034075427623
91856673381263
10553530044307
111a3829309039
128b340112903
13402753462c6
141cb106d3119
15e5ea36c03c
hex80e0f62f93

553530044307 has 4 divisors (see below), whose sum is σ = 738040059080. Its totient is φ = 369020029536.

The previous prime is 553530044273. The next prime is 553530044317. The reversal of 553530044307 is 703440035355.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 553530044307 - 28 = 553530044051 is a prime.

It is a super-2 number, since 2×5535300443072 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (553530044317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92255007382 + ... + 92255007387.

It is an arithmetic number, because the mean of its divisors is an integer number (184510014770).

Almost surely, 2553530044307 is an apocalyptic number.

553530044307 is a deficient number, since it is larger than the sum of its proper divisors (184510014773).

553530044307 is a wasteful number, since it uses less digits than its factorization.

553530044307 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 184510014772.

The product of its (nonzero) digits is 378000, while the sum is 39.

The spelling of 553530044307 in words is "five hundred fifty-three billion, five hundred thirty million, forty-four thousand, three hundred seven".

Divisors: 1 3 184510014769 553530044307