55353900403507 has 4 divisors (see below), whose sum is σ = 55643711400576. Its totient is φ = 55064089406440.

The previous prime is 55353900403499. The next prime is 55353900403643. The reversal of 55353900403507 is 70530400935355.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 55353900403507 - 2³ = 55353900403499 is a prime.

It is a super-4 number, since 4×55353900403507⁴ (a number of 56 digits) contains 4444 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55353900403007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 144905498248 + ... + 144905498629.

It is an arithmetic number, because the mean of its divisors is an integer number (13910927850144).

Almost surely, 2^{55353900403507} is an apocalyptic number.

55353900403507 is a deficient number, since it is larger than the sum of its proper divisors (289810997069).

55353900403507 is a wasteful number, since it uses less digits than its factorization.

55353900403507 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 289810997068.

The product of its (nonzero) digits is 4252500, while the sum is 49.

The spelling of 55353900403507 in words is "fifty-five trillion, three hundred fifty-three billion, nine hundred million, four hundred three thousand, five hundred seven".