Base | Representation |
---|---|
bin | 1101001101001… |
… | …1111110011011 |
3 | 10212020022120011 |
4 | 3103103332123 |
5 | 103140103303 |
6 | 5255142351 |
7 | 1241562064 |
oct | 323237633 |
9 | 125208504 |
10 | 55394203 |
11 | 292a5537 |
12 | 166749b7 |
13 | b626747 |
14 | 74dd56b |
15 | 4ce316d |
hex | 34d3f9b |
55394203 has 4 divisors (see below), whose sum is σ = 55409760. Its totient is φ = 55378648.
The previous prime is 55394201. The next prime is 55394219. The reversal of 55394203 is 30249355.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30249355 = 5 ⋅6049871.
It is a cyclic number.
It is not a de Polignac number, because 55394203 - 21 = 55394201 is a prime.
It is a Smith number, since the sum of its digits (31) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55394201) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 501 + ... + 10537.
It is an arithmetic number, because the mean of its divisors is an integer number (13852440).
Almost surely, 255394203 is an apocalyptic number.
55394203 is a deficient number, since it is larger than the sum of its proper divisors (15557).
55394203 is a wasteful number, since it uses less digits than its factorization.
55394203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15556.
The product of its (nonzero) digits is 16200, while the sum is 31.
The square root of 55394203 is about 7442.7281960313. The cubic root of 55394203 is about 381.2016508427.
The spelling of 55394203 in words is "fifty-five million, three hundred ninety-four thousand, two hundred three".
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