Base | Representation |
---|---|
bin | 110011100110010110… |
… | …110010011111010001 |
3 | 12022000020001011001002 |
4 | 303212112302133101 |
5 | 1401432002404301 |
6 | 41241415151345 |
7 | 4000654062356 |
oct | 634626623721 |
9 | 168006034032 |
10 | 55404341201 |
11 | 21551340640 |
12 | a8a2975555 |
13 | 52bc5ccb61 |
14 | 29783a662d |
15 | 169406b16b |
hex | ce65b27d1 |
55404341201 has 8 divisors (see below), whose sum is σ = 60826076544. Its totient is φ = 50046768720.
The previous prime is 55404341197. The next prime is 55404341243. The reversal of 55404341201 is 10214340455.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 55404341201 - 22 = 55404341197 is a prime.
It is a super-2 number, since 2×554043412012 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55404391201) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16038905 + ... + 16042358.
It is an arithmetic number, because the mean of its divisors is an integer number (7603259568).
Almost surely, 255404341201 is an apocalyptic number.
It is an amenable number.
55404341201 is a deficient number, since it is larger than the sum of its proper divisors (5421735343).
55404341201 is a wasteful number, since it uses less digits than its factorization.
55404341201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32081431.
The product of its (nonzero) digits is 9600, while the sum is 29.
Adding to 55404341201 its reverse (10214340455), we get a palindrome (65618681656).
The spelling of 55404341201 in words is "fifty-five billion, four hundred four million, three hundred forty-one thousand, two hundred one".
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