Base | Representation |
---|---|
bin | 11001001100110000011100… |
… | …10110110100011110010001 |
3 | 21021012111222120220220112002 |
4 | 30212120032112310132101 |
5 | 24230400141140303423 |
6 | 313504444234243345 |
7 | 14446344215054156 |
oct | 1446301626643621 |
9 | 237174876826462 |
10 | 55413908916113 |
11 | 167249a7a44540 |
12 | 626b705b86555 |
13 | 24bc6808c3047 |
14 | d980944ba22d |
15 | 661699dba228 |
hex | 32660e5b4791 |
55413908916113 has 8 divisors (see below), whose sum is σ = 62085362324160. Its totient is φ = 49014759728880.
The previous prime is 55413908916109. The next prime is 55413908916169. The reversal of 55413908916113 is 31161980931455.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 55413908916113 - 22 = 55413908916109 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55413908916013) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 68076054773 + ... + 68076055586.
It is an arithmetic number, because the mean of its divisors is an integer number (7760670290520).
Almost surely, 255413908916113 is an apocalyptic number.
It is an amenable number.
55413908916113 is a deficient number, since it is larger than the sum of its proper divisors (6671453408047).
55413908916113 is a wasteful number, since it uses less digits than its factorization.
55413908916113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 136152110407.
The product of its (nonzero) digits is 3499200, while the sum is 56.
The spelling of 55413908916113 in words is "fifty-five trillion, four hundred thirteen billion, nine hundred eight million, nine hundred sixteen thousand, one hundred thirteen".
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