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55414405041 = 318471468347
BaseRepresentation
bin110011100110111101…
…001011011110110001
312022000220222110000220
4303212331023132301
51401442041430131
641242415003253
74001135446122
oct634675133661
9168026873026
1055414405041
1121556a94766
12a8a6209529
1352c17147a8
142979866049
151694da7e96
hexce6f4b7b1

55414405041 has 4 divisors (see below), whose sum is σ = 73885873392. Its totient is φ = 36942936692.

The previous prime is 55414405003. The next prime is 55414405049. The reversal of 55414405041 is 14050441455.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 55414405041 - 211 = 55414402993 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 55414404993 and 55414405011.

It is not an unprimeable number, because it can be changed into a prime (55414405049) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9235734171 + ... + 9235734176.

It is an arithmetic number, because the mean of its divisors is an integer number (18471468348).

Almost surely, 255414405041 is an apocalyptic number.

It is an amenable number.

55414405041 is a deficient number, since it is larger than the sum of its proper divisors (18471468351).

55414405041 is a wasteful number, since it uses less digits than its factorization.

55414405041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18471468350.

The product of its (nonzero) digits is 32000, while the sum is 33.

Adding to 55414405041 its reverse (14050441455), we get a palindrome (69464846496).

The spelling of 55414405041 in words is "fifty-five billion, four hundred fourteen million, four hundred five thousand, forty-one".

Divisors: 1 3 18471468347 55414405041