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55440000001 = 60119223091
BaseRepresentation
bin110011101000011110…
…110100010000000001
312022002201010210201101
4303220132310100001
51402020120000001
641245131334401
74001566140031
oct635036642001
9168081123641
1055440000001
112156a486621
12a8b28b1401
1352c6b06739
14297d0098c1
151697261a01
hexce87b4401

55440000001 has 4 divisors (see below), whose sum is σ = 55449229104. Its totient is φ = 55430770900.

The previous prime is 55439999921. The next prime is 55440000037. The reversal of 55440000001 is 10000004455.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 55440000001 - 217 = 55439868929 is a prime.

It is a super-2 number, since 2×554400000012 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55440000071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4605535 + ... + 4617556.

It is an arithmetic number, because the mean of its divisors is an integer number (13862307276).

Almost surely, 255440000001 is an apocalyptic number.

It is an amenable number.

55440000001 is a deficient number, since it is larger than the sum of its proper divisors (9229103).

55440000001 is an equidigital number, since it uses as much as digits as its factorization.

55440000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9229102.

The product of its (nonzero) digits is 400, while the sum is 19.

Adding to 55440000001 its reverse (10000004455), we get a palindrome (65440004456).

The spelling of 55440000001 in words is "fifty-five billion, four hundred forty million, one", and thus it is an aban number.

Divisors: 1 6011 9223091 55440000001