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554550455553 = 3184850151851
BaseRepresentation
bin10000001000111011100…
…10000110110100000001
31222000101120111222101020
420010131302012310001
533041204404034203
61102431300500053
755031164045353
oct10043562066401
91860346458336
10554550455553
111a4202303116
128b5859aa629
13403a887bb43
141cbaa0350d3
15e659c31153
hex811dc86d01

554550455553 has 4 divisors (see below), whose sum is σ = 739400607408. Its totient is φ = 369700303700.

The previous prime is 554550455549. The next prime is 554550455573. The reversal of 554550455553 is 355554055455.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 554550455553 - 22 = 554550455549 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 554550455496 and 554550455505.

It is not an unprimeable number, because it can be changed into a prime (554550455573) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92425075923 + ... + 92425075928.

It is an arithmetic number, because the mean of its divisors is an integer number (184850151852).

Almost surely, 2554550455553 is an apocalyptic number.

It is an amenable number.

554550455553 is a deficient number, since it is larger than the sum of its proper divisors (184850151855).

554550455553 is a wasteful number, since it uses less digits than its factorization.

554550455553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 184850151854.

The product of its (nonzero) digits is 18750000, while the sum is 51.

The spelling of 554550455553 in words is "five hundred fifty-four billion, five hundred fifty million, four hundred fifty-five thousand, five hundred fifty-three".

Divisors: 1 3 184850151851 554550455553