Base | Representation |
---|---|
bin | 101000011000011011111… |
… | …0111110001110101011001 |
3 | 201122120121111020001111012 |
4 | 1100300313313301311121 |
5 | 1211412432442142403 |
6 | 15445352333543305 |
7 | 1111656021046421 |
oct | 120606767616531 |
9 | 21576544201435 |
10 | 5550035115353 |
11 | 184a836151763 |
12 | 757773644b35 |
13 | 31349b328171 |
14 | 1528a1c3b481 |
15 | 99580d33ed8 |
hex | 50c37df1d59 |
5550035115353 has 4 divisors (see below), whose sum is σ = 5550069159888. Its totient is φ = 5550001070820.
The previous prime is 5550035115347. The next prime is 5550035115377. The reversal of 5550035115353 is 3535115300555.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5550035115353 - 24 = 5550035115337 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 5550035115353.
It is not an unprimeable number, because it can be changed into a prime (5550035115953) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16776551 + ... + 17104172.
It is an arithmetic number, because the mean of its divisors is an integer number (1387517289972).
Almost surely, 25550035115353 is an apocalyptic number.
It is an amenable number.
5550035115353 is a deficient number, since it is larger than the sum of its proper divisors (34044535).
5550035115353 is a wasteful number, since it uses less digits than its factorization.
5550035115353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34044534.
The product of its (nonzero) digits is 421875, while the sum is 41.
The spelling of 5550035115353 in words is "five trillion, five hundred fifty billion, thirty-five million, one hundred fifteen thousand, three hundred fifty-three".
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