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5550035115353 = 16381133880723
BaseRepresentation
bin101000011000011011111…
…0111110001110101011001
3201122120121111020001111012
41100300313313301311121
51211412432442142403
615445352333543305
71111656021046421
oct120606767616531
921576544201435
105550035115353
11184a836151763
12757773644b35
1331349b328171
141528a1c3b481
1599580d33ed8
hex50c37df1d59

5550035115353 has 4 divisors (see below), whose sum is σ = 5550069159888. Its totient is φ = 5550001070820.

The previous prime is 5550035115347. The next prime is 5550035115377. The reversal of 5550035115353 is 3535115300555.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5550035115353 - 24 = 5550035115337 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 5550035115353.

It is not an unprimeable number, because it can be changed into a prime (5550035115953) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16776551 + ... + 17104172.

It is an arithmetic number, because the mean of its divisors is an integer number (1387517289972).

Almost surely, 25550035115353 is an apocalyptic number.

It is an amenable number.

5550035115353 is a deficient number, since it is larger than the sum of its proper divisors (34044535).

5550035115353 is a wasteful number, since it uses less digits than its factorization.

5550035115353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34044534.

The product of its (nonzero) digits is 421875, while the sum is 41.

The spelling of 5550035115353 in words is "five trillion, five hundred fifty billion, thirty-five million, one hundred fifteen thousand, three hundred fifty-three".

Divisors: 1 163811 33880723 5550035115353