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555012140113 = 31130431372661
BaseRepresentation
bin10000001001110010100…
…11010010110001010001
31222001120202020222112101
420010321103102301101
533043131101440423
61102545152200401
755045501231444
oct10047123226121
91861522228471
10555012140113
111a441997a602
128b694539101
134045040a082
141cc1149565b
15e68552b7ad
hex81394d2c51

555012140113 has 8 divisors (see below), whose sum is σ = 572960100096. Its totient is φ = 537066951600.

The previous prime is 555012140101. The next prime is 555012140159. The reversal of 555012140113 is 311041210555.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 555012140113 - 29 = 555012139601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (555012140713) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 281998 + ... + 1090663.

It is an arithmetic number, because the mean of its divisors is an integer number (71620012512).

Almost surely, 2555012140113 is an apocalyptic number.

It is an amenable number.

555012140113 is a deficient number, since it is larger than the sum of its proper divisors (17947959983).

555012140113 is a wasteful number, since it uses less digits than its factorization.

555012140113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1385735.

The product of its (nonzero) digits is 3000, while the sum is 28.

Adding to 555012140113 its reverse (311041210555), we get a palindrome (866053350668).

The spelling of 555012140113 in words is "five hundred fifty-five billion, twelve million, one hundred forty thousand, one hundred thirteen".

Divisors: 1 31 13043 404333 1372661 42552491 17903617423 555012140113