Base | Representation |
---|---|
bin | 11001010010101011000001… |
… | …10001101110110001000011 |
3 | 21021220221121011121010200001 |
4 | 30221111200301232301003 |
5 | 24242212413210242001 |
6 | 314142100210540431 |
7 | 14500130644504321 |
oct | 1451254061566103 |
9 | 237827534533601 |
10 | 55617155165251 |
11 | 167a3115177769 |
12 | 62a2b88897717 |
13 | 25058a1624aa4 |
14 | da3c55784d11 |
15 | 666ae3326001 |
hex | 329560c6ec43 |
55617155165251 has 4 divisors (see below), whose sum is σ = 55617171003832. Its totient is φ = 55617139326672.
The previous prime is 55617155165191. The next prime is 55617155165267. The reversal of 55617155165251 is 15256155171655.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 55617155165251 - 27 = 55617155165123 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 55617155165192 and 55617155165201.
It is not an unprimeable number, because it can be changed into a prime (55617155165051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36666 + ... + 10546831.
It is an arithmetic number, because the mean of its divisors is an integer number (13904292750958).
Almost surely, 255617155165251 is an apocalyptic number.
55617155165251 is a deficient number, since it is larger than the sum of its proper divisors (15838581).
55617155165251 is a wasteful number, since it uses less digits than its factorization.
55617155165251 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15838580.
The product of its digits is 7875000, while the sum is 55.
The spelling of 55617155165251 in words is "fifty-five trillion, six hundred seventeen billion, one hundred fifty-five million, one hundred sixty-five thousand, two hundred fifty-one".
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