Base | Representation |
---|---|
bin | 10000001100010010010… |
… | …10111000010110000001 |
3 | 1222012001010122121101211 |
4 | 20012021022320112001 |
5 | 33103402120041001 |
6 | 1103330140330121 |
7 | 55123631632150 |
oct | 10061112702601 |
9 | 1865033577354 |
10 | 556352112001 |
11 | 1a4a47299294 |
12 | 8b9a9243941 |
13 | 40604bcbb4a |
14 | 1ccdb41d597 |
15 | e712eb5351 |
hex | 81892b8581 |
556352112001 has 4 divisors (see below), whose sum is σ = 635830985152. Its totient is φ = 476873238852.
The previous prime is 556352111999. The next prime is 556352112011. The reversal of 556352112001 is 100211253655.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 100211253655 = 5 ⋅20042250731.
It is a cyclic number.
It is not a de Polignac number, because 556352112001 - 21 = 556352111999 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (556352112011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39739436565 + ... + 39739436578.
It is an arithmetic number, because the mean of its divisors is an integer number (158957746288).
Almost surely, 2556352112001 is an apocalyptic number.
It is an amenable number.
556352112001 is a deficient number, since it is larger than the sum of its proper divisors (79478873151).
556352112001 is an equidigital number, since it uses as much as digits as its factorization.
556352112001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 79478873150.
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 556352112001 its reverse (100211253655), we get a palindrome (656563365656).
The spelling of 556352112001 in words is "five hundred fifty-six billion, three hundred fifty-two million, one hundred twelve thousand, one".
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