Base | Representation |
---|---|
bin | 11001010011011000000011… |
… | …10010110001000011001011 |
3 | 21022000021000001110100212011 |
4 | 30221230001302301003023 |
5 | 24243111421314430003 |
6 | 314201135203400351 |
7 | 14501645030242321 |
oct | 1451540162610313 |
9 | 238007001410764 |
10 | 55641331405003 |
11 | 168023a10144a3 |
12 | 62a77b53830b7 |
13 | 2507c552a95b6 |
14 | da50aa579d11 |
15 | 66755aa2b46d |
hex | 329b01cb10cb |
55641331405003 has 8 divisors (see below), whose sum is σ = 55733384143440. Its totient is φ = 55549307767200.
The previous prime is 55641331404983. The next prime is 55641331405007. The reversal of 55641331405003 is 30050413314655.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55641331405003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55641331405007) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3446268 + ... + 11097721.
It is an arithmetic number, because the mean of its divisors is an integer number (6966673017930).
Almost surely, 255641331405003 is an apocalyptic number.
55641331405003 is a deficient number, since it is larger than the sum of its proper divisors (92052738437).
55641331405003 is a wasteful number, since it uses less digits than its factorization.
55641331405003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14550317.
The product of its (nonzero) digits is 324000, while the sum is 40.
Adding to 55641331405003 its reverse (30050413314655), we get a palindrome (85691744719658).
The spelling of 55641331405003 in words is "fifty-five trillion, six hundred forty-one billion, three hundred thirty-one million, four hundred five thousand, three".
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