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55670433 = 3713203921
BaseRepresentation
bin1101010001011…
…1011010100001
310212202100110220
43110113122201
5103222423213
65305113253
71244122320
oct324273241
9125670426
1055670433
1129474025
1216788829
13b6c23b0
1475720b7
154d49e23
hex35176a1

55670433 has 16 divisors (see below), whose sum is σ = 91357056. Its totient is φ = 29364480.

The previous prime is 55670371. The next prime is 55670441. The reversal of 55670433 is 33407655.

55670433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 55670433 - 29 = 55669921 is a prime.

It is a super-2 number, since 2×556704332 = 6198394220814978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 55670394 and 55670403.

It is not an unprimeable number, because it can be changed into a prime (55670443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 101688 + ... + 102233.

It is an arithmetic number, because the mean of its divisors is an integer number (5709816).

Almost surely, 255670433 is an apocalyptic number.

It is an amenable number.

55670433 is a deficient number, since it is larger than the sum of its proper divisors (35686623).

55670433 is a wasteful number, since it uses less digits than its factorization.

55670433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 203944.

The product of its (nonzero) digits is 37800, while the sum is 33.

The square root of 55670433 is about 7461.2621586431. The cubic root of 55670433 is about 381.8342368069.

The spelling of 55670433 in words is "fifty-five million, six hundred seventy thousand, four hundred thirty-three".

Divisors: 1 3 7 13 21 39 91 273 203921 611763 1427447 2650973 4282341 7952919 18556811 55670433