Base | Representation |
---|---|
bin | 11001100000111011011011… |
… | …11010000011110010001011 |
3 | 21100122202222102022121000111 |
4 | 30300131231322003302023 |
5 | 24323224114420132133 |
6 | 315155111210415151 |
7 | 14550411543530404 |
oct | 1460355572036213 |
9 | 240582872277014 |
10 | 56107001724043 |
11 | 16971933848536 |
12 | 6361ab54314b7 |
13 | 253cb3805008a |
14 | dbd8443029ab |
15 | 67471288c1cd |
hex | 33076de83c8b |
56107001724043 has 4 divisors (see below), whose sum is σ = 56116231373440. Its totient is φ = 56097772074648.
The previous prime is 56107001724031. The next prime is 56107001724071. The reversal of 56107001724043 is 34042710070165.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-56107001724043 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 56107001723987 and 56107001724005.
It is not an unprimeable number, because it can be changed into a prime (56107001724443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4614815580 + ... + 4614827737.
It is an arithmetic number, because the mean of its divisors is an integer number (14029057843360).
Almost surely, 256107001724043 is an apocalyptic number.
56107001724043 is a deficient number, since it is larger than the sum of its proper divisors (9229649397).
56107001724043 is an equidigital number, since it uses as much as digits as its factorization.
56107001724043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9229649396.
The product of its (nonzero) digits is 141120, while the sum is 40.
The spelling of 56107001724043 in words is "fifty-six trillion, one hundred seven billion, one million, seven hundred twenty-four thousand, forty-three".
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