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56125516207753 = 431305244562971
BaseRepresentation
bin11001100001011101111010…
…11101001101011010001001
321100201112202201120211000101
430300232331131031122021
524324030024122122003
6315211412312205401
714551635420202126
oct1460567535153211
9240645681524011
1056125516207753
111697977478a143
126365601999861
1325417c8a37095
14dc06bd1b574d
15674e47ec011d
hex330bbd74d689

56125516207753 has 4 divisors (see below), whose sum is σ = 57430760770768. Its totient is φ = 54820271644740.

The previous prime is 56125516207729. The next prime is 56125516207771. The reversal of 56125516207753 is 35770261552165.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 56125516207753 - 225 = 56125482653321 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 56125516207694 and 56125516207703.

It is not an unprimeable number, because it can be changed into a prime (56125516207253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 652622281443 + ... + 652622281528.

It is an arithmetic number, because the mean of its divisors is an integer number (14357690192692).

Almost surely, 256125516207753 is an apocalyptic number.

It is an amenable number.

56125516207753 is a deficient number, since it is larger than the sum of its proper divisors (1305244563015).

56125516207753 is a wasteful number, since it uses less digits than its factorization.

56125516207753 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1305244563014.

The product of its (nonzero) digits is 13230000, while the sum is 55.

The spelling of 56125516207753 in words is "fifty-six trillion, one hundred twenty-five billion, five hundred sixteen million, two hundred seven thousand, seven hundred fifty-three".

Divisors: 1 43 1305244562971 56125516207753