5613040742401 has 4 divisors (see below), whose sum is σ = 5613978286512. Its totient is φ = 5612103198292.

The previous prime is 5613040742327. The next prime is 5613040742437. The reversal of 5613040742401 is 1042470403165.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5613040742401 - 2¹³ = 5613040734209 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5613040740401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 468763075 + ... + 468775048.

It is an arithmetic number, because the mean of its divisors is an integer number (1403494571628).

Almost surely, 2^{5613040742401} is an apocalyptic number.

It is an amenable number.

5613040742401 is a deficient number, since it is larger than the sum of its proper divisors (937544111).

5613040742401 is an equidigital number, since it uses as much as digits as its factorization.

5613040742401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 937544110.

The product of its (nonzero) digits is 80640, while the sum is 37.

It can be divided in two parts, 5613040 and 742401, that added together give a square (6355441 = 2521²).

The spelling of 5613040742401 in words is "five trillion, six hundred thirteen billion, forty million, seven hundred forty-two thousand, four hundred one".