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56132523833 = 431305407531
BaseRepresentation
bin110100010001110000…
…100101011100111001
312100212222020122211012
4310101300211130321
51404424411230313
641441550443305
74025005402661
oct642160453471
9170788218735
1056132523833
1121895389a71
12aa66803535
1353a7428c59
142a06d991a1
1516d7e58da8
hexd11c25739

56132523833 has 4 divisors (see below), whose sum is σ = 57437931408. Its totient is φ = 54827116260.

The previous prime is 56132523823. The next prime is 56132523851. The reversal of 56132523833 is 33832523165.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 56132523833 - 214 = 56132507449 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (56132523823) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 652703723 + ... + 652703808.

It is an arithmetic number, because the mean of its divisors is an integer number (14359482852).

Almost surely, 256132523833 is an apocalyptic number.

It is an amenable number.

56132523833 is a deficient number, since it is larger than the sum of its proper divisors (1305407575).

56132523833 is a wasteful number, since it uses less digits than its factorization.

56132523833 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1305407574.

The product of its digits is 388800, while the sum is 41.

The spelling of 56132523833 in words is "fifty-six billion, one hundred thirty-two million, five hundred twenty-three thousand, eight hundred thirty-three".

Divisors: 1 43 1305407531 56132523833