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561355145334643 = 1151032285939513
BaseRepresentation
bin111111110100011001010111…
…0000001111100111101110011
32201121121000202020222212110111
41333220302232001330331303
51042034220314201202033
65305522554343442151
7226145366544404302
oct17750625601747563
92647530666885414
10561355145334643
111529574200521a0
1252b6247a456357
131b12c74209242a
149c89a3c162439
1544d720782e7cd
hex1fe8cae07cf73

561355145334643 has 4 divisors (see below), whose sum is σ = 612387431274168. Its totient is φ = 510322859395120.

The previous prime is 561355145334619. The next prime is 561355145334721. The reversal of 561355145334643 is 346433541553165.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 561355145334643 - 25 = 561355145334611 is a prime.

It is a Smith number, since the sum of its digits (58) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is not an unprimeable number, because it can be changed into a prime (561355145334143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25516142969746 + ... + 25516142969767.

It is an arithmetic number, because the mean of its divisors is an integer number (153096857818542).

Almost surely, 2561355145334643 is an apocalyptic number.

561355145334643 is a deficient number, since it is larger than the sum of its proper divisors (51032285939525).

561355145334643 is a wasteful number, since it uses less digits than its factorization.

561355145334643 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51032285939524.

The product of its digits is 116640000, while the sum is 58.

The spelling of 561355145334643 in words is "five hundred sixty-one trillion, three hundred fifty-five billion, one hundred forty-five million, three hundred thirty-four thousand, six hundred forty-three".

Divisors: 1 11 51032285939513 561355145334643