Base | Representation |
---|---|
bin | 110100010010111100… |
… | …111010100000001001 |
3 | 12100221100220020020111 |
4 | 310102330322200021 |
5 | 1410000022024001 |
6 | 41443543354321 |
7 | 4025340440515 |
oct | 642274724011 |
9 | 170840806214 |
10 | 56152533001 |
11 | 218a5706174 |
12 | aa714529a1 |
13 | 53ab6135b6 |
14 | 2a098c7145 |
15 | 16d9aac851 |
hex | d12f3a809 |
56152533001 has 4 divisors (see below), whose sum is σ = 56266897104. Its totient is φ = 56038168900.
The previous prime is 56152532957. The next prime is 56152533011. The reversal of 56152533001 is 10033525165.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10033525165 = 5 ⋅2006705033.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-56152533001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (56152533011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57181315 + ... + 57182296.
It is an arithmetic number, because the mean of its divisors is an integer number (14066724276).
Almost surely, 256152533001 is an apocalyptic number.
It is an amenable number.
56152533001 is a deficient number, since it is larger than the sum of its proper divisors (114364103).
56152533001 is a wasteful number, since it uses less digits than its factorization.
56152533001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 114364102.
The product of its (nonzero) digits is 13500, while the sum is 31.
The spelling of 56152533001 in words is "fifty-six billion, one hundred fifty-two million, five hundred thirty-three thousand, one".
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