Base | Representation |
---|---|
bin | 110100010010111111… |
… | …101001111010110011 |
3 | 12100221102020201211211 |
4 | 310102333221322303 |
5 | 1410000213022012 |
6 | 41444011020551 |
7 | 4025346522343 |
oct | 642277517263 |
9 | 170842221754 |
10 | 56153251507 |
11 | 218a6056a81 |
12 | aa7173a757 |
13 | 53ab805652 |
14 | 2a09a32d23 |
15 | 16d9ba06a7 |
hex | d12fe9eb3 |
56153251507 has 4 divisors (see below), whose sum is σ = 56275059456. Its totient is φ = 56031443560.
The previous prime is 56153251499. The next prime is 56153251519. The reversal of 56153251507 is 70515235165.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 70515235165 = 5 ⋅14103047033.
It is a cyclic number.
It is not a de Polignac number, because 56153251507 - 23 = 56153251499 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 56153251507.
It is not an unprimeable number, because it can be changed into a prime (56153251547) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60903283 + ... + 60904204.
It is an arithmetic number, because the mean of its divisors is an integer number (14068764864).
Almost surely, 256153251507 is an apocalyptic number.
56153251507 is a deficient number, since it is larger than the sum of its proper divisors (121807949).
56153251507 is a wasteful number, since it uses less digits than its factorization.
56153251507 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 121807948.
The product of its (nonzero) digits is 157500, while the sum is 40.
The spelling of 56153251507 in words is "fifty-six billion, one hundred fifty-three million, two hundred fifty-one thousand, five hundred seven".
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