Base | Representation |
---|---|
bin | 1000000000010110101101100… |
… | …0010110000110100010011011 |
3 | 2201212121210100021010100002101 |
4 | 2000011223120112012202123 |
5 | 1042314231041304304210 |
6 | 5314042514425144231 |
7 | 226441660404062422 |
oct | 20005533026064233 |
9 | 2655553307110071 |
10 | 563340130150555 |
11 | 15355223124aa2a |
12 | 5322311192b077 |
13 | 1b2449918c2394 |
14 | 9d17b447982b9 |
15 | 451db824e8a3a |
hex | 2005ad858689b |
563340130150555 has 4 divisors (see below), whose sum is σ = 676008156180672. Its totient is φ = 450672104120440.
The previous prime is 563340130150487. The next prime is 563340130150561. The reversal of 563340130150555 is 555051031043365.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 563340130150555 - 233 = 563331540215963 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56334013015051 + ... + 56334013015060.
It is an arithmetic number, because the mean of its divisors is an integer number (169002039045168).
Almost surely, 2563340130150555 is an apocalyptic number.
563340130150555 is a deficient number, since it is larger than the sum of its proper divisors (112668026030117).
563340130150555 is a wasteful number, since it uses less digits than its factorization.
563340130150555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 112668026030116.
The product of its (nonzero) digits is 2025000, while the sum is 46.
The spelling of 563340130150555 in words is "five hundred sixty-three trillion, three hundred forty billion, one hundred thirty million, one hundred fifty thousand, five hundred fifty-five".
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