563440121101113 has 4 divisors (see below), whose sum is σ = 751253494801488. Its totient is φ = 375626747400740.

The previous prime is 563440121100931. The next prime is 563440121101153. The reversal of 563440121101113 is 311101121044365.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 563440121101113 - 2³⁴ = 563422941231929 is a prime.

It is not an unprimeable number, because it can be changed into a prime (563440121101153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93906686850183 + ... + 93906686850188.

It is an arithmetic number, because the mean of its divisors is an integer number (187813373700372).

Almost surely, 2^{563440121101113} is an apocalyptic number.

It is an amenable number.

563440121101113 is a deficient number, since it is larger than the sum of its proper divisors (187813373700375).

563440121101113 is a wasteful number, since it uses less digits than its factorization.

563440121101113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 187813373700374.

The product of its (nonzero) digits is 8640, while the sum is 33.

Adding to 563440121101113 its reverse (311101121044365), we get a palindrome (874541242145478).

The spelling of 563440121101113 in words is "five hundred sixty-three trillion, four hundred forty billion, one hundred twenty-one million, one hundred one thousand, one hundred thirteen".