Base | Representation |
---|---|
bin | 101001000100001100101… |
… | …0010110111110000100011 |
3 | 201222120011212012011122101 |
4 | 1102020121102313300203 |
5 | 1214432413404414243 |
6 | 20000453435551231 |
7 | 1121523602243245 |
oct | 122103122676043 |
9 | 21876155164571 |
10 | 5644011404323 |
11 | 1886680331586 |
12 | 771a1bbbb517 |
13 | 31c2c6b89546 |
14 | 157258c7a095 |
15 | 9bc3130054d |
hex | 522194b7c23 |
5644011404323 has 4 divisors (see below), whose sum is σ = 5644030620528. Its totient is φ = 5643992188120.
The previous prime is 5644011404321. The next prime is 5644011404359. The reversal of 5644011404323 is 3234041104465.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5644011404323 - 21 = 5644011404321 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5644011404321) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9160588 + ... + 9757273.
It is an arithmetic number, because the mean of its divisors is an integer number (1411007655132).
Almost surely, 25644011404323 is an apocalyptic number.
5644011404323 is a deficient number, since it is larger than the sum of its proper divisors (19216205).
5644011404323 is a wasteful number, since it uses less digits than its factorization.
5644011404323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19216204.
The product of its (nonzero) digits is 138240, while the sum is 37.
Adding to 5644011404323 its reverse (3234041104465), we get a palindrome (8878052508788).
The spelling of 5644011404323 in words is "five trillion, six hundred forty-four billion, eleven million, four hundred four thousand, three hundred twenty-three".
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