Base | Representation |
---|---|
bin | 110100101010000101… |
… | …101000100011001011 |
3 | 12101221102021220000212 |
4 | 310222011220203023 |
5 | 1411243404212411 |
6 | 41550251151335 |
7 | 4041062655413 |
oct | 645205504313 |
9 | 171842256025 |
10 | 56540694731 |
11 | 21a84825894 |
12 | ab5b44554b |
13 | 5440b6b6b1 |
14 | 2a45289643 |
15 | 170dbd368b |
hex | d2a1688cb |
56540694731 has 4 divisors (see below), whose sum is σ = 56549064264. Its totient is φ = 56532325200.
The previous prime is 56540694709. The next prime is 56540694739. The reversal of 56540694731 is 13749604565.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-56540694731 is a prime.
It is a super-2 number, since 2×565406947312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 56540694731.
It is not an unprimeable number, because it can be changed into a prime (56540694739) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4174625 + ... + 4188146.
It is an arithmetic number, because the mean of its divisors is an integer number (14137266066).
Almost surely, 256540694731 is an apocalyptic number.
56540694731 is a deficient number, since it is larger than the sum of its proper divisors (8369533).
56540694731 is an equidigital number, since it uses as much as digits as its factorization.
56540694731 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8369532.
The product of its (nonzero) digits is 2721600, while the sum is 50.
The spelling of 56540694731 in words is "fifty-six billion, five hundred forty million, six hundred ninety-four thousand, seven hundred thirty-one".
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