Base | Representation |
---|---|
bin | 110101000000001111… |
… | …000111111101011001 |
3 | 12102220022111110011022 |
4 | 311000033013331121 |
5 | 1413024021001213 |
6 | 42051203412225 |
7 | 4053224260520 |
oct | 650017077531 |
9 | 172808443138 |
10 | 56912281433 |
11 | 22155554437 |
12 | b043984075 |
13 | 549cb42297 |
14 | 2a7c7754b7 |
15 | 1731633308 |
hex | d403c7f59 |
56912281433 has 4 divisors (see below), whose sum is σ = 65042607360. Its totient is φ = 48781955508.
The previous prime is 56912281423. The next prime is 56912281451. The reversal of 56912281433 is 33418221965.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 56912281433 - 24 = 56912281417 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (56912281423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4065162953 + ... + 4065162966.
It is an arithmetic number, because the mean of its divisors is an integer number (16260651840).
Almost surely, 256912281433 is an apocalyptic number.
It is an amenable number.
56912281433 is a deficient number, since it is larger than the sum of its proper divisors (8130325927).
56912281433 is an equidigital number, since it uses as much as digits as its factorization.
56912281433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8130325926.
The product of its digits is 311040, while the sum is 44.
The spelling of 56912281433 in words is "fifty-six billion, nine hundred twelve million, two hundred eighty-one thousand, four hundred thirty-three".
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