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57000626987 = 89640456483
BaseRepresentation
bin110101000101100000…
…001000101100101011
312110010110201212110212
4311011200020230223
51413214130030422
642104041131335
74055346222653
oct650540105453
9173113655425
1057000626987
11221a0405797
12b069489b4b
1354b5235165
142a8a3b1363
1517392849e2
hexd45808b2b

57000626987 has 4 divisors (see below), whose sum is σ = 57641083560. Its totient is φ = 56360170416.

The previous prime is 57000626983. The next prime is 57000626999. The reversal of 57000626987 is 78962600075.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 57000626987 - 22 = 57000626983 is a prime.

It is a super-3 number, since 3×570006269873 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (57000626983) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 320228153 + ... + 320228330.

It is an arithmetic number, because the mean of its divisors is an integer number (14410270890).

Almost surely, 257000626987 is an apocalyptic number.

57000626987 is a deficient number, since it is larger than the sum of its proper divisors (640456573).

57000626987 is an equidigital number, since it uses as much as digits as its factorization.

57000626987 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 640456572.

The product of its (nonzero) digits is 1270080, while the sum is 50.

The spelling of 57000626987 in words is "fifty-seven billion, six hundred twenty-six thousand, nine hundred eighty-seven".

Divisors: 1 89 640456483 57000626987