Base | Representation |
---|---|
bin | 110101001001111000… |
… | …110100001011111001 |
3 | 12110022121012001010111 |
4 | 311021320310023321 |
5 | 1413341444033213 |
6 | 42115230144321 |
7 | 4060231512250 |
oct | 651170641371 |
9 | 173277161114 |
10 | 57074205433 |
11 | 222289a0323 |
12 | b08a0520a1 |
13 | 54c75576bb |
14 | 2a96085797 |
15 | 174096aa3d |
hex | d49e342f9 |
57074205433 has 4 divisors (see below), whose sum is σ = 65227663360. Its totient is φ = 48920747508.
The previous prime is 57074205401. The next prime is 57074205467. The reversal of 57074205433 is 33450247075.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 57074205433 - 25 = 57074205401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (57074205233) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4076728953 + ... + 4076728966.
It is an arithmetic number, because the mean of its divisors is an integer number (16306915840).
Almost surely, 257074205433 is an apocalyptic number.
It is an amenable number.
57074205433 is a deficient number, since it is larger than the sum of its proper divisors (8153457927).
57074205433 is an equidigital number, since it uses as much as digits as its factorization.
57074205433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8153457926.
The product of its (nonzero) digits is 352800, while the sum is 40.
The spelling of 57074205433 in words is "fifty-seven billion, seventy-four million, two hundred five thousand, four hundred thirty-three".
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