Base | Representation |
---|---|
bin | 11001111101111011110010… |
… | …10101000101100001111011 |
3 | 21111012001102212021211201111 |
4 | 30332331321111011201323 |
5 | 24441041211144134011 |
6 | 321241013222501151 |
7 | 15012413036255212 |
oct | 1476757125054173 |
9 | 244161385254644 |
10 | 57103625771131 |
11 | 1721656a071aa5 |
12 | 64a30948947b7 |
13 | 25b2b05a92334 |
14 | 1015b8a23c079 |
15 | 6905e2a4b121 |
hex | 33ef7954587b |
57103625771131 has 8 divisors (see below), whose sum is σ = 57248741844000. Its totient is φ = 56958589416960.
The previous prime is 57103625771117. The next prime is 57103625771141. The reversal of 57103625771131 is 13117752630175.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-57103625771131 is a prime.
It is a super-2 number, since 2×571036257711312 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (57103625771141) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18495096 + ... + 21360613.
It is an arithmetic number, because the mean of its divisors is an integer number (7156092730500).
Almost surely, 257103625771131 is an apocalyptic number.
57103625771131 is a deficient number, since it is larger than the sum of its proper divisors (145116072869).
57103625771131 is a wasteful number, since it uses less digits than its factorization.
57103625771131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39859349.
The product of its (nonzero) digits is 926100, while the sum is 49.
The spelling of 57103625771131 in words is "fifty-seven trillion, one hundred three billion, six hundred twenty-five million, seven hundred seventy-one thousand, one hundred thirty-one".
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