Base | Representation |
---|---|
bin | 11001111111011111001111… |
… | …01100111000010111000001 |
3 | 21111101011020210111212121220 |
4 | 30333233213230320113001 |
5 | 24442430032340004303 |
6 | 321321323212305253 |
7 | 15016313111203155 |
oct | 1477574754702701 |
9 | 244334223455556 |
10 | 57157017109953 |
11 | 17237178095102 |
12 | 64b14b5472229 |
13 | 25b7b64314807 |
14 | 10185b3123065 |
15 | 691bb9ed7053 |
hex | 33fbe7b385c1 |
57157017109953 has 4 divisors (see below), whose sum is σ = 76209356146608. Its totient is φ = 38104678073300.
The previous prime is 57157017109919. The next prime is 57157017109957. The reversal of 57157017109953 is 35990171075175.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 57157017109953 - 222 = 57157012915649 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (57157017109957) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9526169518323 + ... + 9526169518328.
It is an arithmetic number, because the mean of its divisors is an integer number (19052339036652).
Almost surely, 257157017109953 is an apocalyptic number.
It is an amenable number.
57157017109953 is a deficient number, since it is larger than the sum of its proper divisors (19052339036655).
57157017109953 is a wasteful number, since it uses less digits than its factorization.
57157017109953 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19052339036654.
The product of its (nonzero) digits is 10418625, while the sum is 60.
The spelling of 57157017109953 in words is "fifty-seven trillion, one hundred fifty-seven billion, seventeen million, one hundred nine thousand, nine hundred fifty-three".
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