Base | Representation |
---|---|
bin | 101001100111100111001… |
… | …0110100010011101001011 |
3 | 202020211111001121012111201 |
4 | 1103033032112202131023 |
5 | 1222204142223021041 |
6 | 20055432204005031 |
7 | 1130155335255235 |
oct | 123171626423513 |
9 | 22224431535451 |
10 | 5720063485771 |
11 | 1905957796a58 |
12 | 784705830777 |
13 | 32652710657b |
14 | 15abd157b255 |
15 | 9dbd2dd5631 |
hex | 533ce5a274b |
5720063485771 has 4 divisors (see below), whose sum is σ = 5720079318952. Its totient is φ = 5720047652592.
The previous prime is 5720063485757. The next prime is 5720063485793. The reversal of 5720063485771 is 1775843600275.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5720063485771 - 211 = 5720063483723 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5720063485751) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7361721 + ... + 8101546.
It is an arithmetic number, because the mean of its divisors is an integer number (1430019829738).
Almost surely, 25720063485771 is an apocalyptic number.
5720063485771 is a deficient number, since it is larger than the sum of its proper divisors (15833181).
5720063485771 is a wasteful number, since it uses less digits than its factorization.
5720063485771 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15833180.
The product of its (nonzero) digits is 9878400, while the sum is 55.
The spelling of 5720063485771 in words is "five trillion, seven hundred twenty billion, sixty-three million, four hundred eighty-five thousand, seven hundred seventy-one".
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